floorn
Round a double-precision floating-point number to the nearest multiple of 10^n toward negative infinity.
Usage
var floorn = require( '@stdlib/math/base/special/floorn' );
floorn( x, n )
Rounds a double-precision floating-point number to the nearest multiple of 10^n
toward negative infinity.
// Round a value to 4 decimal places:
var v = floorn( 3.141592653589793, -4 );
// returns 3.1415
// If n = 0, `floorn` behaves like `floor`:
v = floorn( 3.141592653589793, 0 );
// returns 3.0
// Round a value to the nearest thousand:
v = floorn( 12368.0, 3 );
// returns 12000.0
Notes
When operating on floating-point numbers in bases other than
2
, rounding to specified digits can be inexact. For example,var x = -0.2 - 0.1; // returns -0.30000000000000004 // Should round to -0.3: var v = floorn( x, -16 ); // returns -0.3000000000000001
Examples
var randu = require( '@stdlib/random/base/randu' );
var floorn = require( '@stdlib/math/base/special/floorn' );
var x;
var n;
var v;
var i;
for ( i = 0; i < 100; i++ ) {
x = (randu()*100.0) - 50.0;
n = floorn( randu()*5.0, 0 );
v = floorn( x, -n );
console.log( 'x: %d. Number of decimals: %d. Rounded: %d.', x, n, v );
}
C APIs
Usage
#include "stdlib/math/base/special/floorn.h"
stdlib_base_floorn( x, n )
Rounds a double-precision floating-point number to the nearest multiple of 10^n
toward negative infinity.
double y = stdlib_base_floorn( 3.141592653589793, -4 );
// returns 3.1415
// If n = 0, `floorn` behaves like `floor`:
double y = stdlib_base_floorn( 3.141592653589793, 0 );
// returns 3.0
The function accepts the following arguments:
- x:
[in] double
input value. - n:
[in] int32_t
integer power of 10.
double stdlib_base_floorn( const double x, const int32_t n );
Examples
#include "stdlib/math/base/special/floorn.h"
#include <stdio.h>
int main() {
const double x[] = { 3.14, -3.14, 0.0, 0.0/0.0 };
double y;
int i;
for ( i = 0; i < 4; i++ ) {
y = stdlib_base_floorn( x[ i ], -2 );
printf( "floorn(%lf, -2) = %lf\n", x[ i ], y );
}
}