isOddf

Test if a finite single-precision floating-point number is an odd number.

Usage

var isOddf = require( '@stdlib/math/base/assert/is-oddf' );

isOddf( x )

Tests if a finite single-precision floating-point number is an odd number.

var bool = isOddf( 5.0 );
// returns true

bool = isOddf( -2.0 );
// returns false

bool = isOddf( 0.0 );
// returns false

bool = isOddf( NaN );
// returns false

Notes

The function assumes a finite number. If provided positive or negative infinity, the function will return true, when, in fact, the result is undefined. If x can be infinite, wrap the implementation as follows:

function check( x ) {
    return (
        x < Infinity &&
        x > -Infinity &&
        isOddf( x )
    );
}

var bool = check( Infinity );
// returns false

bool = check( -Infinity );
// returns false

Examples

var randu = require( '@stdlib/random/array/discrete-uniform' );
var isOddf = require( '@stdlib/math/base/assert/is-oddf' );

var x = randu( 100, 0, 100 );

var i;
for ( i = 0; i < 100; i++ ) {
    console.log( '%d is %s', x[ i ], ( isOddf( x[ i ] ) ) ? 'odd' : 'not odd' );
}

C APIs

Usage

#include "stdlib/math/base/assert/is_oddf.h"

stdlib_base_is_oddf( x )

Tests if a finite single-precision floating-point number is an odd number.

#include <stdbool.h>

bool out = stdlib_base_is_oddf( 1.0f );
// returns true

out = stdlib_base_is_oddf( 4.0f );
// returns false

The function accepts the following arguments:

x: [in] float input value.

bool stdlib_base_is_oddf( const float x );

Examples

#include "stdlib/math/base/assert/is_oddf.h"
#include <stdio.h>
#include <stdbool.h>

int main( void ) {
    const float x[] = { 5.0f, -5.0f, 3.14f, -3.14f, 0.0f, 0.0f / 0.0f };

    bool b;
    int i;
    for ( i = 0; i < 6; i++ ) {
        b = stdlib_base_is_oddf( x[ i ] );
        printf( "Value: %f. Is Odd? %s.\n", x[ i ], ( b ) ? "True" : "False" );
    }
}